Question

V The formula v= √ 2gh gives the velocity v, in feet per second, of an object after it falls h feet accelerated by gravity g, in feet per second squared. If g is approximately 32 feet per second squared, find how far an object has fallen if its velocity is 56 feet per second The object has fallen from its initial position.

Answer 1

49 ft

Explanation:

Given:

g = 32 ft/m^2

v = 56 ft/s

Replacing:

`\begin{gathered} 56=\sqrt[]{2\cdot32\cdot h} \\ 56=\sqrt[]{64h} \end{gathered}`

We solve for h which would be how far the object fell:

`\begin{gathered} √(h)=\frac{56}{\sqrt[]{64}}=(56)/(8)=7 \\ h=7^2 \\ h=49 \end{gathered}`

The object was 49 feet high