Question

Can you please help me out with a question

Answer 1

`J\text{. Center(-9,-5) and r=8}`

Step-by-step explanation

the equation of a circle is given by:

`\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ \text{where} \\ (h,k)\text{ is the center} \\ \text{and r is the radius} \end{gathered}`

so

`\begin{gathered} (x+9)^2+(y+5)^2=64 \\ +9=-h \\ so,\text{ h=-9} \\ and \\ 5=-k \\ k=-5 \end{gathered}`

so, the center is

`(-9,-5)`

Step 2

now, the radius

`\begin{gathered} (x+9)^2+(y+5)^2=64 \\ so \\ 64=r^2 \\ \text{square root in both sides} \\ \sqrt[]{64}=\sqrt[\square]{r^2} \\ 8=r \\ \text{hence, the radisu is 8} \\ r=8 \end{gathered}`

I hope this helps you