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If the rate of change of Cl2 is –0.0500M/s, what is the rate of change of NO?2NO (g) + Cl2 (g) -------> 2NOCl (g) ______ M/s

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The question requires us to calculate the rate of change of NO, given that the rate of change of Cl2 is -0.0500 M/s.

The balanced chemical reaction provided is:


2NO_{(g)_{}}+Cl_(2(g))\to2NOCl_((g))_{}

From the stochiometry of the reaction we can say that Δ[NO] = 2/1 Δ[Cl2], thus we can calculate the rate of change of NO as:


\Delta\lbrack NO\rbrack=2\Delta\lbrack Cl_2\rbrack\to\Delta\lbrack NO\rbrack=2*(-0.0500M/s)=-0.100M/s

Therefore, the rate of change of NO is -0.100 M/s.

User Aravindh S
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