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In a basketball tournament, Team A scored 5 less than twice as many points as Team B. Team C scored 80 more points than Team B. The combined score for all three teams was 983 points. Let the variable b represent Team B’s total points. The equation representing this scenario is (2b – 5) + b + (b + 80) = 983. Team B scored 227 total points.

User Diyarbakir
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2 Answers

17 votes
17 votes

Answer: Let us assume number of points scored by Team B = b points.

Number of points scored by Team A 5 fewer than twice as many points as Team B, that is "5 less than 2b" = (2b-5) points .

Team C scored 80 more points than Team B, that is " 80 more than b" = (b+80) points.

Total number of points scored by all teams = 983 points.

Therefore, we can setup an equation:

(2b-5) + b + (b+80) = 983.

Therefore, an equation to represent this scenario using the variable b to represent Team B’s total points is (2b-5) + b + (b+80) = 983.

Team A= 2b-5

Team B= b

Team C= b+80

The equation representing this scenario is (2b-5)+ b + (b+80)= 983

User Lucas Noetzold
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2.8k points
20 votes
20 votes

Answer:

b=227

Explanation:

User Jbyler
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2.7k points