Question

How do I solve this problem? Hint: 1. Draw the forces - load: weight downwards, tension uphelicopter: weight downwards, tension downwards, thrust up2. The combined mass is equal to the two masses (kgs) added together3. The tensions cancel, so to find the net force add the two weights together and subtract from the thrust.4. Calculate the acceleration using a = Fnet / m5. If the thrust was greater than the two weights the speed will be increasing. If the weights are greater, the speed will decrease. 6. The tension can be calculated by isolating the load and using T = W ± ma (Use + if the speed is increasing, and - if the speed is decreasing).

Answer 1

A force diagam is shown below:

where,

Th: Thrust force of the helicopter = 40000N

fg1: weight of the helicopter = (3000kg)(9.8m/s^2) = 29400N

T: tension in the cable

fg2: weight of the load = (700kg)(9.8m/s^2) = 6860N

Based on the given information and the force diagram, you can conclude:

Three forces are acting on the helicopter.

Two forces are acting on the load.

The forces are unbalanced.

The mass of the system is the sum of the mass of the helicopter and the load:

mass of the system = 3000kg + 700kg = 3700kg

The net force is given by (based on the information of point 3):

Fnet = Th - (fg1 + fg2)

Fnet = 40000N - (29400N + 6860N)

Fnet = 40000N - 36260N

Fnet = 3740N

The acceleration is:

a = 3740N/3700kg = 1.01 m/s^2

The speed of the system increases because there is an acceleration on te system. The motion of the system is upward because the net force points up ward.

The tension in the cable is given by:

T = fg2 - m2*a

T = 6860N - (700kg)(1.011 ms=/s^2)

T = 6860N - 707.7N

T = 6152.3N