SOLUTION
The Data set given is
4.9,2.7,6.2,5,4.7,5.4,6.5,3.8,12
The minimum of the data set is the lowest data in the distribution
![\text{minimun}=2.7](https://img.qammunity.org/2023/formulas/mathematics/college/mv70wbnte9mid9ffnbk0xzsv87c23ha8le.png)
The first quartile is given by
![Q_1=((N)/(4)+1)^(th)](https://img.qammunity.org/2023/formulas/mathematics/college/vkq1sarj1xk85dmiluz3fq1g2frly1csl9.png)
where N=frequency of the data=9
![Q_1=(9)/(4)+1=1.25+1=2.25^(th)](https://img.qammunity.org/2023/formulas/mathematics/college/yflfntuju2sne0a4u59slkswmdqtt1en9a.png)
Then the first quartile becomes
![Q_1=4.7](https://img.qammunity.org/2023/formulas/mathematics/college/98eqz04yswjd2qi7joorfeqyvoq7gefdrg.png)
The median is the middle number after arrangement
![2.7,3.8,4.7,4.9,5.0,5.4,6.2,6.5,12](https://img.qammunity.org/2023/formulas/mathematics/college/jnqk3jr5bv8le5gv430f1zwzcow1zcvuqo.png)
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