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Find the minimum, first quartile, median, third quartile, and maximum of the data set below.4.92.76.2.54.75.46.53.812type an integer or decimal

User Overdose
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1 Answer

2 votes

SOLUTION

The Data set given is

4.9,2.7,6.2,5,4.7,5.4,6.5,3.8,12

The minimum of the data set is the lowest data in the distribution


\text{minimun}=2.7

The first quartile is given by


Q_1=((N)/(4)+1)^(th)

where N=frequency of the data=9


Q_1=(9)/(4)+1=1.25+1=2.25^(th)

Then the first quartile becomes


Q_1=4.7

The median is the middle number after arrangement


2.7,3.8,4.7,4.9,5.0,5.4,6.2,6.5,12
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User Dexygen
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