Question

A survey was conducted that asked 1019(Use ascending order Round to two decimal places as needed)

Answer 1

Given

n = 1019

`\bar{x}=13.1,s=16.6`

Find

Construct a 95% confidence interval for the mean number of books people read .

Step-by-step explanation

first , we need to solve for the margin of error

`\begin{gathered} E=t_{(\alpha)/(2)}.(s)/(√(n)) \\ \\ E=1.96*(16.6)/(√(1019)) \\ \\ E=(32.536)/(32.921779399) \\ \\ E=1.02 \end{gathered}`

Lower bound =

`\bar{x}-E=13.1-1.02=12.08`

upper bound =

`\bar{x}+E=13.1+1.02=14.12`

Final Answer

Therefore , the 95% confidence interval is (12.08,14.12)