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2 Given f(x) = 45x" - 41x + 4 and g(x) = 9x - 1, where g(x) = 0, find (x). .

User Alswl
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1 Answer

6 votes

As given functions are:


\begin{gathered} f(x)=45x^2-41x+4 \\ g(x)=9x-1 \end{gathered}

Given that g(x)=0, So:


\begin{gathered} g(x)=0 \\ 9x-1=0 \\ x=(1)/(9) \end{gathered}

Now put the value of x in f(x):


\begin{gathered} f(x)=45((1)/(9))^2-41((1)/(9))+4 \\ f(x)=45((1)/(81))-(41)/(9)+4 \\ f(x)=(5)/(9)+4-(41)/(9) \\ f(x)=(5+36-41)/(9) \\ f(x)=(41-41)/(9) \\ f(x)=0 \end{gathered}

So the value of f(x) is 0.

User Charles Madere
by
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