The formula for the statistical z-score is :
![z=\frac{\mu_1-\mu_2}{\sqrt[]{(\sigma^2_1)/(n_1)+(\sigma^2_2)/(n_2)}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/sm0giw7xy6equgsr1h4obs4g5ccg0oztuz.png)
Where n1 and n2 are the sample sizes
u1 and u2 are the sample means
and
o1 and o2 are the standard deviation
From the given problem, we have :
u1 = 3.16
u2 = 3.28
n1 = 103
n2 = 225
o1 = 0.52
o2 = 0.46
Substitute the values to the formula :
![\begin{gathered} z=\frac{3.16-3.28}{\sqrt[]{(0.52^2)/(103)+(0.46^2)/(225)}}=(-0.12)/(0.0597) \\ z=-2.01 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/7epzntpyhu8lald2qg0zzzbrxtcxq76srf.png)
Therefore, the answer is z = -2.01