Question

Deon's gas tank is  1/5  full. After he buys  13  gallons of gas, it is  7/10  full. How many gallons can Deon's tank hold?​

Answer 1

26 gallons.

Explanation:

7/10 - 1/5

= 7/10 - 2/10

= 5/10 = 1/2.

So the tank holds 2*13 = 26 gallons.

Answer 2

Answer/Step-by-step explanation:

We start with the variable "x". Let's call "x" Dan's full tank.

So we know that right now he has 1/5x or 1/5 of a full tank.

After adding 13 gallons, at the end, he has 7/10x, or 7/10 of a full tank

So we start with

(1/5)x + 13 = 7/10x

Let's subtract 1/5x from both sides

13 = 7/10x - 1/5x

Remember, we need to use common denominators to subtract, so 1/3 becomes 2/10

13 = 7/10-2/10x

Now we simplify to get

13 = 5/10x

Multiply the reciprocal of 5/10 to both sides which is 10/5

13 * 10/5= x

Answer is 26 gallons.

Therefore, Deon's tank can hold 26 gallons.