Question

The length of a new rectangular playing field is 2 yards longer than quadruple the width. If the perimeter of the rectangular playing field is 544 yards, what are its dimensions?

Answer 1

My first step is to draw a picture

We know the length is 4 times the width plus 2

We are told the perimeter is 544

P = 2L + 2 W

Substitute in for L

544 = 2 ( 4W + 2) + 2W

Distribute

544 = 8W + 4 + 2W

Combine like terms

544 = 10W + 4

Subtract 4 from each side

544-4 = 10W +4-4

540 = 10W

Divide each side by 10

540/10 = 10W/10

54 = W

The width is 54 yards

Now find the length

L = 4W +2 = 4(54) +2 = 218 yards