Explanation:
What do you mean "no real roots" ?
if I understand correctly we have
2x² + 5kx + k = 0
the solutions for such a quadratic equating are
x = (-b ± sqrt(b² - 4ac))/(2a)
a = 2
b = 5k
c = k
so, we get
x = (-5k ± sqrt(25k² - 8k))/4
why would that have no real solutions ?
e.g. k = 2
x = (-10 ± sqrt(100 - 16))/4 = (-10 ± sqrt(84))/4
since the sqrt is a little bit bigger than 9 we get 2 negative solutions for x. but still real.
I don't understand what your need here.