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Please help me solve: Part CA sign in a freight elevator states that the maximum capacity of the elevator is 2,500 pounds. Use the average weight of a box as 75 pounds and the average weight of a crate as 160 pounds to complete the following parts.If there are 13 average-weight boxes on the elevator, what is the maximum number of average-weight crates that can also be on the elevator given its maximum capacity? Please explain.

User Grigson
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1 Answer

4 votes

Let

x ----> number of average-weight crates

so

we have that


75(13)+160x\leq2,500

solve for x


\begin{gathered} 975+160x\leq2,500 \\ 160x\leq2,500-975 \\ 160x\leq1,525 \\ x\leq9.53 \end{gathered}

therefore

the maximum number of average-weight crates is 9

User SeedyROM
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