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How many grams are in 0.787 moles of kcn

How many grams are in 0.787 moles of kcn-example-1
User GlobooX
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1 Answer

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Answer:

=> moles = Given mass/molar mass

=> 0.787 = Given mass/(39 + 12 + 14)

=> 0.787 = Given mass/65

=> mass = 0.787 × 65

=> mass = 51.155 g

User TrueCamelType
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