The given equation to be balanced is
C
4
H
10
+
O
2
→
C
O
2
+
H
2
O
We begin by counting the number of
C atoms on both sides. We have 4C on the left and 1C on the right.
⇒
C
4
H
10
+
O
2
→
4
C
O
2
+
H
2
O
Now count the number of H atoms on both sides. We have 10H on the left and 2 H on the right.
⇒
C
4
H
10
+
O
2
→
4
C
O
2
+
5
H
2
O
Now, O's turn. We have 2 O on the left and 13 O on the right.
⇒
C
4
H
10
+
13
2
O
2
→
4
C
O
2
+
5
H
2
O
or
2
C
4
H
10
+
13
O
2
→
8
C
O
2
+
10
H
2
O