Question

Find the areas of the sectors formed by NMP. Round your answer to the hundredth of a square centimeter.

Answer 1

Consider that the area of a sector of a circle is given by:

`A=(\theta)/(360)\pi r^2`

where θ is the angle of the sector and r is the radius.

For θ=40 and r = 8cm, you obtain:

`A=(40)/(360)\pi(8cm)^2=22.34cm^2`

The area of the small sector is about 22.34 cm^2.

Now, for θ=320 and r = 8cm, you obtain:

`A^(\prime)=(320)/(360)\pi(8cm)^2=178.72cm^2`

The area of the small sector is about 178.72 cm^2.