Question

Write a paragraph proof to 4(x – 3) + 1 prove that if PQ = 4(x - 3) + 1, QR = x + 10, and x = 7, P then PQ = QR.

Answer 1

We have the following:

`\begin{gathered} PR=PQ+QR \\ PQ=4(x-3)+1 \\ QR=x+10 \end{gathered}`

Now,

x = 7

replacing:

`\begin{gathered} PQ=4(7-3)+1=4\cdot4+1=17 \\ QR=7+10=17 \end{gathered}`

Therefore, PQ = QR