Question

Solve the following polynomial equation by grouping and factoring. 36y^3−49y=0

Answer 1

Given:

`36y^3-49y=0`

solve for y:

`\begin{gathered} 36y^3-49y=0 \\ y(36y^2-49)=0 \\ y=0;36y^2-49=0 \end{gathered}`

Value of y is zero and

`\begin{gathered} 36y^2-49=0 \\ 36y^2=49 \\ y^2=(49)/(36) \\ y=\pm\sqrt[]{(49)/(36)} \\ y=\pm\sqrt[]{1.361111} \\ y=\pm1.166 \\ y=1.166,y=-1.166 \end{gathered}`