Question

What is f(g(x)) when f(x)=3x+1 and g(x)=4x^2-4

Answer 1

f(x)=3x+1 = (-1/3, 0)

g(x)=4x^2-4 = (1, 0), (-1, 0)

Explanation:

Hope this helped!

Answer 2

• f(g(x)) = 12x² - 11

Explanation:

Given:

• f(x) = 3x + 1
• g(x) = 4x² - 4

Find f(g(x)):

• f(g(x)) = f(4x² - 4) = 3(4x² - 4) + 1 = 12x² - 12 + 1 = 12x² - 11