Question

the length of a rectangle is 6 meters less than twice its width if the perimeter is 48 M what are the dimensions of the rectangle

Answer 1

The perimeter is given by:

`\begin{gathered} P=2w+2l \\ where \\ w=width \\ l=length=2w-6 \\ so\colon \\ 48=2w+2(2w-6) \\ 48=2w+4w-12 \\ 48=6w-12 \\ solve_{\text{ }}for_{\text{ }}w \\ 6w=60 \\ w=(60)/(6) \\ w=10 \end{gathered}`

So:

`\begin{gathered} l=2(10)-6 \\ l=14 \end{gathered}`

width = 10m

l = lenght = 14m