Perimeter = 18 ft
Area = 20 ft ^2
Perimeter = 2l + 2w
Area = lw
Substitution
18 = 2l + 2w
20 = lw
Solve for l
20/w = l
18 = 2(20/w) + 2w
18 = 40/w + 2w
18w = 40 + 2w^2
2w^2 - 18w + 40 = 0
w^2 - 9w + 20 = 0
(w - 5)(w - 4) = 0
w1 = 5 w2 = 4
Conclusion
width = 4 ft
length = 5 ft
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