Question

How many molecules of carbon monoxide are needed to react with excess iron (III) oxide?

Answer 1

1) Balance the chemical equation.

`Fe_2O_3+3CO\rightarrow2Fe+3CO_2`

2) Convert grams of Fe into moles of F2.

`\text{mol Fe= 11.6 g Fe}_{}\cdot\frac{1\text{ mol Fe}}{55.845\text{ g Fe}}=\text{ 0.2077 mol Fe}`

0.2077 mol Fe was produced.

3) Moles of CO needed to produce 0.2077 mol Fe.

`\text{mol CO}_{}=0.2077\text{ mol Fe}\cdot\frac{3\text{ mol CO}}{2\text{ mol Fe}}=0.31155\text{mol CO}`

4) Convert moles of CO into molecules of CO

`\text{molecules of CO=0.31155 mol CO}\cdot\frac{6.022\cdot10^(23)}{1\text{ mol CO}}=\text{ 1.8761}\cdot10^(23)\text{ molecules of CO}`

1.88*10^23 molecules of carbon monoxide are needed to react with excess iron (III) oxide.

.