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A reaction produced 11.92 grams of O₂, when it was calculated that it would produce 15.9 grams of O₂. What was the percent yield?

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Answer

The percent yield = 74.97%

Step-by-step explanation

A reaction produced 11.92 grams of O₂ implies the actual yield = 11.92 grams of O₂

When it was calculated that it would produce 15.9 grams of O₂ implies the theoretical yield = 15.9 grams of O₂

Therefore, the percent yield is


\begin{gathered} Percent\text{ }yield=\frac{Actual\text{ }yield}{Theoretical\text{ }yield}*100\% \\ \\ Percent\text{ }yield=\frac{11.92\text{ }grams}{15.9\text{ }grams}*100\% \\ \\ Percent\text{ }yield=0.7497*100\% \\ \\ Percent\text{ }yield=74.97\% \end{gathered}

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