Perimeters and areas
Square perimeter = 4*side length
= 4L
Triangle area = base * height / 2
= B*H/2
Then 4L = B*H/2
We know that
B = L + 2
and H = 6 in
1. 4L = B*H/2
2. B = L + 2
3. H = 6 in
Replacing the second and third eq in the first
4L = (L + 2) * (6) / 2
4L = (6L + 12) / 2
4L = 3L + 6
L = 6 in
ANSWER the square area (given by L*L) is (6 in)* (6 in) = 36 i