Given,
The equations of line are,
y = -1/6x + 2
y = 6x + 4
The standard form of equation of line is: y = mx+c
On comparing the equation of line to the standard equation then,
The slope of line is y = -1/6x + 2 is -1/6.
The slope of line is y = 6x + 2 is 6.
When the line are parallel then
![m_1=m_2](https://img.qammunity.org/2023/formulas/mathematics/college/bb136i6nrncquza4si9ea0meh8h3qjcl3x.png)
When the line are perpendicular then,
![m_1* m_2=-1](https://img.qammunity.org/2023/formulas/mathematics/college/drvgj3vmsiwqhbbe0hcgk6m0betp6bgxci.png)
Substituting the value of slopes then,
![6*(-1)/(6)=-1](https://img.qammunity.org/2023/formulas/mathematics/college/m5wlvzl830wkp51royjrdjhundq17srs82.png)
Hence, the product of the slope of the line is equal to -1. So, the line are perpendicular to each other.