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Writing the equation of the line through two given points(1,-3) (5,-1). y=mx+b form

User LennonR
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Given points (1,-3) and (5,-1).

Since the slope of the line passing through two points


(x_1,y_1)(x_2,y_2)

The slope of the equation is


\begin{gathered} m=(y_2-y_1)/(x_2-x_1) \\ m=(-1-(-3))/(5-1) \\ m=(2)/(4) \\ m=(1)/(2) \end{gathered}

Therefore, the slope of the line is 1/2.

Now, use the slope and the point (1,-3) to find the y-intercept.


\begin{gathered} y=mx+c \\ -3=(1)/(2)*1+c \\ c=-3-(1)/(2) \\ c=-(-7)/(2) \end{gathered}

Write the equation in slope-intercept form as


\begin{gathered} y=mx+c \\ y=(1)/(2)x-(7)/(2) \end{gathered}

User Hands
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