Let x be correct questions of Joe and y be correct quiz question of Joe. The in equality for Joe and Hannah together questions is,
![x+y<11](https://img.qammunity.org/2023/formulas/mathematics/college/jlmbk3tvjp06yslarqbpofcx2wn3oz63ci.png)
Joe got 3 more questions correct than Hannah, means equaltion is,
![y=x+3](https://img.qammunity.org/2023/formulas/mathematics/high-school/fnhkdd43nsc0tka2tffgnbr91n7tm902aa.png)
So inequality obtained is,
![\begin{gathered} x+x+3<11 \\ 2x+3<11 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/1fcltztmmcftg11nnwy728w3ooew1cfa1l.png)
Thus option F is incorrect.
Let x be number of dimes and y be number of quarters. So inequality for collection of coins is,
![x+y<11](https://img.qammunity.org/2023/formulas/mathematics/college/jlmbk3tvjp06yslarqbpofcx2wn3oz63ci.png)
The number of quarters are,
![y=3x](https://img.qammunity.org/2023/formulas/mathematics/high-school/x3q8kt3l366jfmm89tfr8zil9wuf8fwkg6.png)
So resultant inequality is,
![\begin{gathered} x+3x<11 \\ 4x<11 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ao8jgo6abvoo0nifaf8rdknw114j9n4cut.png)
Thus option G is incorrect.
Let larger number be y. So sum of numbers is less than 11, means
![x+y<11](https://img.qammunity.org/2023/formulas/mathematics/college/jlmbk3tvjp06yslarqbpofcx2wn3oz63ci.png)
The equation of larger number in terms of smaller number is,
![y=2x+3](https://img.qammunity.org/2023/formulas/mathematics/high-school/30zzxuyb9lxdanrb1oj8xocd58463jib7b.png)
Substitute the value of y in the inequality to obtain the desired inequality.
![\begin{gathered} x+2x+3<11 \\ 3x+3<11 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/872mgg5qtqy2ufoncq27ues7ogp0d6nphz.png)
Thus inequality obtained is 3x + 3 < 11.
Thus option H is correct.
Correct option : Two numbers have a sum that is less than 11. The larger number is 3 more than twice he smaller number. What s the smaller number, x?