Question

The given point (-3,-4) is on the terminal side of an angle in standard position. How do you determine the exact value of the six trig functions of the angle?

Answer 1

In this problem -3 will be the adyacent side, -4 will be the opposite side and wwe can calculate the hypotenuse so:

`\begin{gathered} h^{}=\sqrt[]{(-3)^2+(-4)^2} \\ h=\sqrt[]{9+16} \\ h=\sqrt[]{25} \\ h=5 \end{gathered}`

So the trigonometric function will be:

`\begin{gathered} \sin (\theta)=-(4)/(5) \\ \cos (\theta)=-(3)/(5) \\ \tan (\theta)=(4)/(3) \\ \csc (\theta)=-(5)/(4) \\ \sec (\theta)=-(5)/(3) \\ \cot (\theta)=(3)/(4) \end{gathered}`