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Last year, Susan had $20,000 to invest. She invested some of it in an account that paid 10% simple interest per year, and she invested the rest in an account that paid 7% simple interest per year. After one year, she received a total of $1790 in interest. How much did she invest in each account?

Last year, Susan had $20,000 to invest. She invested some of it in an account that-example-1
User Euan Smith
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Last year, Susan had $20,000 to invest. She invested some of it in an account that paid 10% simple interest per year, and she invested the rest in an account that paid 7% simple interest per year. After one year, she received a total of $1790 in interest. How much did she invest in each account?

Let

x ------> amount invested in an account that paid 10% simple interest per year

20,000-x ------> amount invested in an account that paid 7% simple interest per year

so

The formula of simple interest is equal to

I=P(rt)

In this problem we have that

10%=0.10

7%=0.07

x*(0.1)+(20,000-x)*(0.07)=1,790

solve for x

0.10x+1,400-0.07x=1,790

0.03x=1,790-1,400

0.03x=390

x=$13,000

therefore

amount invested in an account that paid 10% simple interest per year was $13,000

and

amount invested in an account that paid 7% simple interest per year was $7,000

User Fantasia
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