Question

How do I answer the question -x^2-6x+16=0 using the quadratic formula?

Answer 1

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Answer:

x = -8 or 2

Explanation:

Compare your equation to the standard form equation.

-x^2 -6x +16 = 0 . . . . . . your equation

ax^2 +bx +c = 0 . . . . . . standard form equation

Identify the values of 'a', 'b', and 'c'.

a = -1

b = -6

c = 16

Fill in these values in the quadratic formula and do the arithmetic.

`x = (-b\pm√(b^2-4ac))/(2a)\\\\x=(-(-6)\pm√((-6)^2-4(-1)(16)))/(2(-1))=(6\pm√(100))/(-2)\\\\x=-3\pm5=\{-8,2\}`

The solutions are x = -8 and x = 2.