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Are the graphs of the equations parallel, perpendicular, or neither?x -3y = 6 and x - 3y = 9

User Basj
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The equation of a line in Slope-Intercept form, is:


y=mx+b

Where "m" is the slope of the line and "b" is the y-intercept.

By definition:

- The slopes of parallel lines are equal and the y-intercepts are different.

- The slopes of perpendicular lines are opposite reciprocals.

For this case you need to rewrite the equations given in the exercise in Slope-Intercept form by solving for "y".

- Line #1:


\begin{gathered} x-3y=6 \\ -3y=-x+6 \\ y=(-x)/(-3)+((6)/(-3)) \\ \\ y=(x)/(3)-2 \end{gathered}

You can identify that:


\begin{gathered} m_1=(1)/(3) \\ \\ b_1=-2 \end{gathered}

- Line #2:


\begin{gathered} x-3y=9​ \\ -3y=-x+9 \\ y=(-x)/(-3)+((9)/(-3)) \\ \\ y=(x)/(3)-3 \end{gathered}

You can identify that:


\begin{gathered} m_2=(1)/(3) \\ \\ b_2=-3_{}_{} \end{gathered}

Therefore, since:


\begin{gathered} m_1=m_2 \\ b_1\\e b_2 \end{gathered}

You can conclude that: The graphs of the equation are parallel.

User Mkhurmi
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