Volume of the cone = 50.29 mm³
Step-by-step explanation:
![\text{Volume = 1/3}\pi r^2\text{ h}](https://img.qammunity.org/2023/formulas/mathematics/high-school/7kc7807gi5q5wpfijtvuuo3gmd1k5jkuex.png)
radius = r = ?
height = 3mm
slant height = 5mm
To get the radius, we would apply pythagoras' theorem:
Hypotenuse² = opposite² + adjacent²
hypotenuse = 5mm
opposite = 3mm
adjacent = radius = ?
5² = 3² + radius²
25 = 9 + radius²
25 - 9 = radius²
16 = radius²
radius = √16
radius = 4
![\text{Volume of the cone = }(1)/(3)*(22)/(7)*4^2*3](https://img.qammunity.org/2023/formulas/mathematics/high-school/2v9frqz88qqhcxbyqltrx8ejmtqdh1s1rj.png)
![\text{Volume of the cone = }50.29mm^3](https://img.qammunity.org/2023/formulas/mathematics/high-school/pwl03jdpk35qawhilvglnim8bxca6r7vl5.png)