Question

Hi i need some help. on the “select” part, the options are 1997-2006.

Answer 1

From the given table that represents the population in a small coastal communityfor the period 1997 to 2006, let's answer the following questions.

(a) Average rate of change of the population between 1999 and 2002.

To find the average rate of change, apply the formula below:

`Average=(y2-y1)/(x2-x1)`

Where:

x1 = 1999

x2 = 2002

y1 = the population in 1999 = 1,336

y2 = the population in 2002 = 1,483

Thus, we have:

`\begin{gathered} Average=(1483-1336)/(2002-1999) \\ \\ Average=(147)/(3) \\ \\ Average=49 \end{gathered}`

Therefore, the average rate of change of the population between 1999 and 2002 is

49

(b) What was the average rate of change of the population between 2001 and 2005.

To find the average rate of change, apply the formula:

`Average=(y2-y1)/(x2-x1)`

Where:

x1 = 2001

x2 = 2005

y1 = population in 2001 = 1591

y2 = population in 2005 = 801

Thus, we have:

`\begin{gathered} Average=(801-1591)/(2005-2001) \\ \\ \text{Average}=(-790)/(4) \\ \\ \text{Average}=-197.5 \end{gathered}`

Therefore, the average rate of change in the population between 2001 and 2005 was -197.5

(c) For what period of time was the population increasing.

From the given table, we can see the table was increasing from 1997 to 2001

The population was increasing from 1997 to 2001

(d) For what period was the population decreasing.

From the table, the population was decreasing from 2002 to 2006

The population was decreasing from 2001 to 2006

ANSWER:

• (a) 49

,

• (b) -197.5

,

• (c) 1997 to 2001

,

• (d) 2001 to 2006