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In AOPQ, 0 = 500 cm, p = 600 cm and q=380 cm. Find the measure of P to thenearest 10th of a degree.

User Mhaddl
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Answer: Triangle has three sides, which are:


\begin{gathered} O=500\operatorname{cm} \\ P=600\operatorname{cm} \\ Q=380\operatorname{cm} \\ \end{gathered}

We need to find the angle p, that is right across the side P:


\angle A=\arccos ((b^2+c^2+a^2)/(2bc))=0.97895\text{rad}=56.09\text{degres}

This is the value of angle A

In AOPQ, 0 = 500 cm, p = 600 cm and q=380 cm. Find the measure of P to thenearest-example-1
User Weng
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