The regular pentagon can divide into 5 congruent isosceles triangles
The equal sides of each triangle have length r and vertex angle of measure 72 degrees
Then we will use the sine rule of the area to find the area of each triangle, then multiply it by 5 to get the area of the pentagon
Since the radius is 7mm, then
r = 7

Substitute r by 7

Round it to the nearest whole number
A = 117 mm^2
The area of the pentagon is 117 mm^2