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5 votes
Distance between (11,-5) and (0,1)

1 Answer

3 votes

Here,point can be written as:


\begin{gathered} x1=11, \\ y1=-5 \\ x2=0 \\ y2=1 \end{gathered}

The formula for the distance between the points as follows;


\begin{gathered} d=√((x1-x2)^2+(y1-y2)^2) \\ d=√((11-0)^2+(-5-1)^2) \\ d=√(121+36) \\ d=√(157) \\ d=12.53 \end{gathered}

Thus, the distance between the point is 12.53.

User Yohei Onishi
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4.8k points