Question

Kyle has a container of flour in the shape of a cylinder.

Answer 1

Part A:

The volume of a cylinder is given below as

`\begin{gathered} V_(cylinder)=\pi* r^2* h \\ r=(d)/(2)=(10in)/(2)=5in \\ h=8in \end{gathered}`

By substituting the values , we will have

`\begin{gathered} V_(cyl\imaginaryI nder)=\pi r^2h \\ V_{cyl\mathrm{i}nder}=\pi*5^2*8 \\ V_{cyl\mathrm{i}nder}=\pi*200 \\ V_{cyl\mathrm{i}nder}=628.3in^3 \end{gathered}`

Hence,

The volume = 628.3in³

Part B:

To determine the weight of the flour in ounces, we will use the relation below

`\begin{gathered} 0.13ounce=1in^3 \\ x=628.3in^3 \\ cross\text{ multiply, we will have} \\ x=0.13*628.3 \\ x=81.679 \\ x\approx81.7ounces \end{gathered}`

Hence,

The weight = 81.7 ounces