Question

A negative charge of .30 c and a positive charge of .50 are separated by .40What is the force between the charges?

Answer 1

Given:

The negative charge q1 = 0.3 C

The positive charge q2 = 0.5 C

The distance between the charges is 0.4 m

To find the magnitude of the force between them.

Explanation:

The formula to calculate the magnitude of the force is

`F=(kq1q2)/(r^2)`

Here, k is Coulomb's constant whose value is

`k=\text{ 9}*10^9Nm^2C^(-2)`

On substituting the values, the magnitude of force will be

`\begin{gathered} F=(9*10^9*0.3*0.5)/((0.4)^2) \\ =8.4375\text{ }*10^9\text{ N} \end{gathered}`

Final Answer: The magnitude of the force is 8.4375 x 10^(9) N.