Question

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Answer 1

Let:

`k\cdot RT=TU`

Where:

k = Constant of proportionality

`\begin{gathered} k\cdot4=6 \\ solve_{\text{ }}for_{\text{ }}k \\ k=(6)/(4) \\ k=(3)/(2) \end{gathered}`

So:

`\begin{gathered} k\cdot RS=UV \\ (3)/(2)(6)=UV \\ (18)/(2)=UV \\ UV=9 \end{gathered}`