Question 1

I will provide another picture with the questions to this problemBefore beginning: please note that this is lengthy, pre calculus practice problem

I will provide another picture with the questions to this problemBefore beginning-example-1

Question 2

$\begin{gathered} \text{For }Albert \\ For\text{ \$1,000} \\ t=10years=120\text{ months} \\ i=1.2\text{\%=0.012} \\ C=1,000(1+0.012)^(120) \\ C=1,000(1.012)^(120) \\ C=\text{\$}4,184.67 \\ \text{For \$}500 \\ \text{lost 2\%=0.02 over 10 years, hence} \\ C1=500(1-0.02) \\ C1=500(0.98) \\ C1=\text{ \$}490 \\ \text{For \$}500 \\ i=0.8\text{ \%=0.008} \\ t=10 \\ C2=500(1+0.008)^(10) \\ C2=500(1.008)^(10) \\ C2=\text{ \$}541.47 \\ \text{Total}=\text{\$}4,184.67+\text{ \$}490+\text{ \$}541.47 \\ \text{Total}=\text{ \$5,216.14} \\ After\text{ 10 year Albert has \$5,216.14} \\ \text{For Marie} \\ For\text{ \$1,500} \\ Quaterly \\ 1\text{ year has }3\text{ quaternions, hence in 10 years are 30 quaternions, t=30} \\ i=1.4\text{ \% monthly, hence } \\ \frac{1.4\text{ \% }}{3}=0.467\text{ \%=0.00467} \\ C=1,500(1+0.00467)^(30) \\ C=1,500(1.00467)^(30) \\ C=\text{ \$}1,725.02 \\ \text{For \$500} \\ C2=500(1+0.04) \\ C2=500(1.04) \\ C2=\text{ \$}520 \\ \text{Total}=\text{ \$}1,725.02+\text{ \$}520 \\ \text{Total}=\text{ \$}2,245.02 \\ After\text{ 10 year Marie has \$2,245.02} \\ \text{For }Hans \\ t=10 \\ i=0.9\text{ \%=0.009} \\ C=2,000(1+0.009)^(10) \\ C=2,000(1.009)^(10) \\ C=\text{\$}2,187.47 \\ After\text{ 10 year Hans has \$}2,187.47 \\ \text{For }Max \\ For\text{ 1,000} \\ t=10 \\ i=0.5\text{ \%=0.005} \\ C=1,000e^((-0.005)(10)) \\ C=\text{\$}951.23 \\ \text{For 1,000} \\ i=1.8\text{ \%=0.018} \\ t=20 \\ C1=1,000(1+0.018)^(20) \\ C1=1,000(1.018)^(20) \\ C1=\text{ \$1,428.75} \\ \text{Total =\$}951.23+\text{ \$1,428.75} \\ \text{Total}=\text{ \$2,379.98} \\ After\text{ 10 year Max has \$2,379.98} \\ \\ At\text{ the end of the competition is \$10,000 richer than his siblings} \end{gathered}$

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