Question

A 72.5 kg student sits at a desk 1.25 m away from a 80.0 kg student. What is the magnitude of the gravitational force between the two students?

Answer 1

Given:

The mass of one student is,

`m_1=72.5\text{ kg}`

The mass of the other student is,

`m_2=80.0\text{ kg}`

The distance between them is,

`d=1.25\text{ m}`

The gravitational force between them is,

`F=G(m_1m_2)/(d^2)`

Here the gravitational constant is,

Substituting the values we get,

`\begin{gathered} F=((6.6*10^(-11))*72.5*80.0)/((1.25)^2) \\ =2.5*10^(-7)\text{N} \end{gathered}`

Hence the second option is correct.