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· A) A highway noise barrier is 120 m long is constructed in 2pieces. One piece is 45 m longer than the other one. Findthe length of each piece. B) If you are to construct arectangle with each of the sizes of the pieces being thelength and width then what is the perimeter? c) What would bethe area of that rectangle? (Note: Use an Equation to solve)

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A) Let the length of one piece be x. if one piece is 45 m longer than the other one, it means that the length of the other one would be (x + 45) m

Given that the total length of both pieces is 120m, then the equation would be

x + x + 45 = 120

2x + 45 = 120

2x = 120 - 45 = 75

x = 75/2

x = 37.5

Thus, the length of each piece are

37.5 m

37.5 + 45 = 82.5 m

B) The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(length + width)

Given that

length = 82.5

width = 37.5

then

perimeter = 2(82.5 + 37.5) = 2 * 120

perimeter of rectangle= 240 m

C) the formula for determining area of a rectangle is expressed as

Area = length * width

Area of rectangle = 82.5 * 37.5 = 3093.75 cm^2

User Fareed Radzi
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