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24 votes
24 votes
In the Isoceles triangle, the legs

19x+10 and 5x+16. If the base is
he inches long, the perimeter of the
triangle is
inches

User Johnny Five
by
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1 Answer

22 votes
22 votes

Check the picture below.

since we know that x = 3/7, we can then plug that on either of the twin legs, since it's an isosceles, and get the length of each leg, so say let's plug it in 5x + 16


5x + 16\implies 5\left( \cfrac{3}{7} \right)+16\implies \cfrac{38}{7}+16\implies \cfrac{38+112}{7}\implies \cfrac{150}{7}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\\stackrel{\textit{both legs}}{\cfrac{150}{7}+\cfrac{150}{7}}+\stackrel{\textit{base}}{6}\implies \cfrac{150+150+42}{7}\implies \cfrac{342}{7}\implies 48(6)/(7)\impliedby \textit{perimeter}

In the Isoceles triangle, the legs 19x+10 and 5x+16. If the base is he inches long-example-1
User Le Curious
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