Given
AD = 6.4
BD = 3.6
Find
AC,BC and DC
Step-by-step explanation
Using Pythogoras theorem in triangle ADC
![AC^2=DC^2+6.4^2------(1)](https://img.qammunity.org/2023/formulas/mathematics/college/fmdhdmdlclqnvmjd4wxek1zr0lfrdivs8k.png)
Using PT in triangle BDC
![BC^2=DC^2+3.6^2-------(2)](https://img.qammunity.org/2023/formulas/mathematics/college/3lnwsretk59qpr75t23dzx51pf5gdqt1ho.png)
Adding equation (1) and (2)
![\begin{gathered} AC^2+BC^2=DC^2+3.6^2+DC^2+6.4^2 \\ AC^2+BC^2=2DC^2+53.92 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/bhcqk7mzjr2h76crqut1r6lvy289nqtqmf.png)
Using PT in triangle ABC
![10^2=AC^2+BC^2](https://img.qammunity.org/2023/formulas/mathematics/college/r5efx5ny3trz6ry6k9trbynwxw6moojmxb.png)
Equating above 2 equations
![\begin{gathered} 100=2DC^2+53.92 \\ DC^2=23.04 \\ DC=4.8 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/yvdvout7jsc9uvgid7yz7zqjok3dwuwawe.png)
Putting this value of DC in equation (2)
![\begin{gathered} BC^2=4.8^2+3.6^2 \\ BC^2=23.04+12.96 \\ BC=6 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/p32b598rbabdtjzbhstkf6okdo7nuubfny.png)
![\begin{gathered} 10^2=AC^2+BC^2 \\ 100=AC^2+36 \\ AC=8 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/elcvf8xx2x7nuork6agzkpecqd2ft2r8p7.png)
Final Answer
AC = 8
BC = 6
DC = 4.8