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A salt solution has a molarity of 1.5 M. How many mole of this salt are present in 2.0 L of this solution.A. 1.5 molesB. 2.0 molesC. 3.0 moles D. 0.75 mole

User RSquared
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1 Answer

4 votes

Answer:


C\text{ : 3.0 moles}

Step-by-step explanation:

Here, we want to get the number of moles present in the solution

Mathematically:


Number\text{ of moles = molarity }*\text{ volume in L}

From the question:

We have the molarity as 1.5 M

We have the volume as 2.0 L

Thus, we have the number of moles as:


1.5\text{ }*\text{ 2 = 3.0 moles}

User Yussan
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