Question

Use the given conditions to write an equation for the line in point-slope form and general form. Passing through (8,-4) and perpendicular to the line whose equation is x-6y-5=0

Answer 1

y + 4 = -6 (x - 8)

Explanation:

Change the equation to the slope intercept form for a line

x - 6y 5 = 0 Add 5 to both sides

x - 6y = 5 Subtract x from both sides

-6y = -x + 5 Divide both sides by -6

y =
`(1)/(6)` c -
`(5)/(-6)` Your slope is
`(1)/(6)`

A perpendicular slope is the opposite reciprocal of
`(1)/(6)`, that would be -6

y -
`y_(1)` = m( x -
`x_(1)`) Plug is -4 for
`y_(1)` and 8 for
`y_(1)`

y - -4) -6(x-8)

y + 4= -6 (x -8)