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How do you write (x+1)^(2)-(2x+3)(x-4) in standard form?

1 Answer

3 votes

Answer:

- x² + 7x + 13

Explanation:

a parabola in standard form id expressed as

ax² + bx + c ( a≠ 0 )

given

(x + 1)² - (2x + 3)(x - 4) ← expand factors using FOIL

= x² + 2x + 1 - (2x² - 5x - 12) ← distribute parenthesis by - 1

= x² + 2x + 1 - 2x² + 5x + 12 ← collect like terms

= - x² + 7x + 13 ← in standard form

User Kevin Moore
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