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in the equation dy+3x=2, for what value of d is the graph of the equation parallel to the graph of x-3y=0? the y axis?

User Abhinsit
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2 Answers

12 votes
12 votes

Final answer:

For the graph of dy + 3x = 2 to be parallel to the graph of x - 3y = 0, the value of d must be -9.

Step-by-step explanation:

To determine the value of d for which the graph of dy + 3x = 2 is parallel to the graph of x - 3y = 0 or the y-axis, we first need to understand the concept of the slope of a line.

The slope is a measure of how steep a line is, and it is calculated as the rise over the run (change in y over change in x). For two lines to be parallel, their slopes must be equal.

First, we convert the equation x - 3y = 0 into slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept. This yields y = (1/3)x, meaning the slope of this line is 1/3. For the graph of dy + 3x = 2 to be parallel to this line, it must also have a slope of 1/3.

By rearranging dy + 3x = 2 into slope-intercept form, we get y = (-3/d)x + (2/d).

Therefore, to have a slope of 1/3, d must be -9 (-3/-9 = 1/3).

User Umang Mehta
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2.6k points
14 votes
14 votes

Answer:

-9

Step-by-step explanation:

The slope of the the solving equation is triple the slope of the given equation. Therefore, the y coefficient must also be triple of the other y coefficient.

User Nemec
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2.8k points