Question

Find the
inverse of the function
y = 2x^2+2

Answer 1

Answer: (It could just be the first one you did not give enough information for your question so I wasn't sure)

`\sqrt{(x-2)/(2) } , -\sqrt{(x-2)/(2) }`

Explanation:

Replace y with x:

`y=2x^(2) +2` ⇒
`x=2y^(2) +2`

Subract 2 from both sides:

`x-2=2y^(2) +2 -2\\` ⇒
`x-2=2y^(2)`

Divide 2 from both sides:

`(x-2)/(2) = (2y^(2) )/(2)` ⇒
`(x-2)/(2) =y^(2)`

Square root both sides:

`\sqrt{(x-2)/(2) } =\sqrt{y^(2) }` ⇒
`y=\sqrt{(x-2)/(2) }`

I hope this helps you have a bright blessed day.