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Identify the vertex and the y-intercept of the graph of f(x) = -(x + 2)2 + 3. Use the drop-down menus to show your answer.​

User Michael Karcher
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1 Answer

23 votes
23 votes

Answer:

Vertex: (-2, 3)

Y-intercept: (0, -1)

Explanation:

The vertex form of the quadratic function is f(x) = a(x - h)² + k, where:

(h, k) = vertex

a = determines the direction of the opening of the graph (a < 1 = the graph opens down; a > 1 = graph opens upward).

h = determines the horizontal translation of the graph.

k = determines the vertical translation of the graph.

Given the quadratic function in vertex form, f(x) = -(x + 2)² + 3, where: a = -1, h = -2, and k = 3.

The vertex (h, k ) of the graph occurs at point (-2, 3).

The y-intercept is the point on the graph where it crosses the y-axis. It is also the value of y when x = 0. In order to find out the y-intercept, set x = 0:

f(0) = -(0 + 2)² + 3

f(0) = -(2)² + 3

f(0) = -4 + 3

f(0) = -1

The y-intercept of the graph is (0, -1).

User Evil Dog Pie
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